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There are a few ways to go about factoring. You can decide what works best for you. I always find the prime factorization first. Let's look at a random number: 108

The prime factorization can be found by using a factor tree.

108

54,2

27,2,2

9,3,2,2

3,3,3,2,2

2^2 x 3^3 = 108

Half of the factors will be less than the square root, half greater. If the number is a perfect square, there will be an equal number of factors on either side of the square root. In this case, the square root is between 10 and 11.

Adding one to the exponents of the prime factorization and multiplying them will tell you how many factors there are. In this case, the exponents are 2 and 3. Add one to each. 3 x 4 = 12

108 has 12 factors. Six of them are 10 or less, six of them are 11 or greater. All we have to do is divide the numbers one through ten into 108. If the result (quotient) turns out to be an integer, you've found a factor pair. Knowing the rules of divisibility will make that even easier.

108 is divisible by...

1 because everything is.

2 because it's even.

3 because its digits add up to a multiple of 3.

4 because its last two digits are a multiple of 4.

6 because it's a multiple of 2 and 3.

9 because its digits add up to a multiple of 9.

That's six factors less than 10. Divide them into 108. That's the rest of them.

(108,1)(54,2)(36,3)(27,4)(18,6)(12,9)

1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108

Notice that all of those numbers, except for 1, can also be found in the prime factorization.

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7y ago
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10y ago

The simplest way is to try out different factors. Try if the number is divisible by 2, 3, 5, 7 (trying out those factors is enough for numbers up to 120); if you find one, divide by that factor, and separate the rest of the number. For example, since 88 is a multiple of 2, you divide it by 2 to get 44, so you write:

88 = 2 x 44

Then continue looking whether there are additional factors for 44, in this case (or whatever is left, for other numbers).

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Q: A way to break down a number into its factors?
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Does it matter what two factors you select to a factor tree explain?

No. Since you are going to keep factoring until all the factors are prime, it doesn't matter what you start with. Example: 36 You can start with 6 and 6, which you would then break down into 2,3,2,3. You could start with 9 and 4, which you would then break down to 3,3,2,2. Either way, you're going to wind up with two twos and two threes. 2 x 2 x 3 x 3 is the prime factorization for 36.


How do you do factor trees?

You break down the factors of a number until all the factors are prime. For example: 24 / \ 6 4 / \ 3x2 x 2x2 This factor tree was very easy, but there will be harder ones in the future. When all the numbers at the bottom of the tree are prime, you are finished. Factor trees may also be used to find the prime factorization of a number. PS: I'm sorry about the appearance of the tree. Once I published it, it became, and stayed that way. Real factor trees don't look like this. 24 is broken down into 6x4, because they are the factors. Since 24 is composite, you do not have to use 6x4. Then we break 6 into 3x2, and 4 into 2x2. Then 3x2x2x2 is a prime factorization. And you are also done with the factor tree!


Which number between 21 and 40 has the most factors?

The number with the most factors between 21 and 40 is 30. Factors of a number are the numbers that can divide the original number without leaving a remainder. The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30, giving it a total of 8 factors, which is the highest among the numbers between 21 and 40.


What is 49 divisible by?

A number being divisible by another number is a different way of saying the factors of a number. Factors are numbers you can multiply together to get another number. 49: 1, 7, 49


What is the difference between foil and factor?

FOIL is a way to combine terms through multiplication. Factoring is a way to break down terms through division.

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What does break the second number down into factors to work out 18x18?

Ok I'll guess 18x18 = 18x9x2 = (18x9)x2 = 162x2 = 324 or = 18x6x3 = (18x6)x3 = 108x3 = 324 same answer either way


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Does it matter what two factors you select to a factor tree explain?

No. Since you are going to keep factoring until all the factors are prime, it doesn't matter what you start with. Example: 36 You can start with 6 and 6, which you would then break down into 2,3,2,3. You could start with 9 and 4, which you would then break down to 3,3,2,2. Either way, you're going to wind up with two twos and two threes. 2 x 2 x 3 x 3 is the prime factorization for 36.


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List all the factors of 62?

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