1, 2, 4, 8, 16, 32, and 64.
The factors of 64 are 1, 2, 4, 8, 16, 32 and 64
To tackle this question, you first need to break the number down into its prime factors. In this case we have 64 = 2x2x2x2x2x2 To find the greater factors, you need to multiply any combination of these. That gives us the factors as 2, 4, 8, 16, 32 and 64 Adding these up for the sum gives us 126 Thus the sum of all even factors of 64 is 126.
The factors of 27 are 1,3,9, and 27 The factors of 64 are 1,2,4,8,16,32, and 64. 1 is the only common factor of 27 and 64.
The Factors of 64 are 1, 2, 4, 8, 16, 32 and 64.
No, 32 and 64 have other factors as well.
The factors of 64 are 1, 2, 4, 8, 16, 32, and 64.
1,2,4,8,16,32,64
Seven factors.
All the factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. All the factors of 64 are 1, 2, 4, 8, 16, 32, and 64.
The factors of 64 are all 2s and the factors of 81 are all 3s. The greatest common factor is 1, since they have no factors in common. ■
Yes.
1, 2, 4, 8, 16, 32, 64 All but 1 and 2 are composite.
The trivial answers are 0 and 1, 1x1x1x1.... = 1 so it can have 64 factors. Also 2x2x2x2x.... (64 times) = 264 is also a number with 64 factors If you mean 64 prime factors ... 1x2x3x5x7x .... use the first 64 prime numbers.
16 and 32 are factors of 64, so that set will include them all. 1,2,4,8,16 1,2,4,8,16,32 1,2,4,8,16,32,64
It is 126.
1 and 2 all the common factors of 64,12,18