when the object reaches maximum height, the velocity of the object is 0 m/s.
It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.
Where there is and you have the objects initial velocity then you can use :
v^2 = u^2+2.a.s
v = Velocity when it reaches Max. height so v = 0
u = Initial Velocity (m/s)
a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2
And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
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Fetch means "go and bring back." Catch means "grab ball when thrown."
I think you're referring to the C/C++ concept of "dangling pointers." This is when you allocate some memory to a pointer, then deallocate that memory, but don't change the pointer. This causes any attempted use of the pointer to return an unused memory address. There is no such concept in Java, since the programmer has little to no control over how memory is allocated or freed. The closest thing I can think of is if you're using a class such as a Reader, in which you can close the object (Reader.close()) and then still have a reference to it. But in this case (and other similar cases) attempting to use the Reader further will result in an IOException being thrown.
A heap is unspecified - it is a group of things placed, thrown or lying one on another. It can be a great quantity or a small number. It can refer to a 'heap' of food on a plate to a 'heap' of stone as in a hill. A similar word would be 'pile'
Hippasus, However Pythagoras could not accept the existence of irrational numbers, because he believed that all numbers had perfect values. But he could not disprove Hippasus' "irrational numbers" and so Hippasus was thrown overboard and drowned.