Multiples of 50 are the only numbers that are both. All other multiples of 5 aren't.
9 of them.
90. All numbers that are multiples of 3, 5 & 9 are multiples of their lowest common multiple lcm(3, 5, 9) = 45 → multiples of 45 between 49 and 95 is 2 x 45 = 90.
All of the numbers that end in 5 are multiples of 5 which means that they have more than two factors.
The first action sequence in the flow chart is to remove all multiples of 2 from numbers greater than 2. The next sequence removes removes all multiples of 3 from all numbers greater than 3. The third sequence removes all multiples of 5 from the remaining numbers greater than 5. The fourth sequence removes all multiples of 7 from the remaining numbers greater than 7. Additional sequences are added as needed to remove multiples of as many primes as desired in ascending order.
No as 5, 15 and an infinite amount of other multiples of 5 are odd
All of the numbers between 5 and 45 are multiples, even if only of themselves.
All the even numbers and all the odd multiples of 5.
Even numbers have to end with 2, 4, 6, 8, or 0. And multiples of 5 have to end in 5 or 0.
All decimals, and all whole numbers that do not end in zero or 5, are not multiples of 5 .
Even. Numbers ending in zero are multiples of 10, and 10 = 5 x 2, so all multiples of 10 are even.
It is not possible it has to be an even number.Plus it has no times or division numbers.
Multiples of 50 are the only numbers that are both. All other multiples of 5 aren't.
All multiples of 5 are numbers ending in either 5 or 0.
60 and all multiples of 60.
Not AllTo find out if all numbers that have 5 as a factor have 2 as a factor, you can list the multiples of each. 5's multiples are 5, 10, 15, 20...2's multiples are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20...5 and 15 are multiples of 5, but not 2, so all numbers that have 5 as a factor DO NOT have 2 as a factor.It is not really necessary to write that all out because the fact that 5 is an odd number and 2 is only a factor of even numbers indicates that all numbers that have 5 as a factor would not have 2 as a factor. Only the multiples of 5 that are even have 2 as a factor also.
All non-zero numbers have an infinite amount of multiples. There are no numbers with exactly five.