Infinity is not just really big number - and consequently the concepts of rational vs irrational cannot be applied to it. It is a marvelously useful concept with great utility in mathematics but don't confuse it for being the same as a number that we could write out and categorize just because we have a symbol for representing it. When you stick infinity into an equation you get things like "limits" rather than a fixed answer; for example - for the function f(x) = (x-1)/x, if x = ∞ you don't actually get a value for the function- rather you get a limit that it approaches as x goes off to infinity; in this case the limit as x approaches infinity is 1. For the function f(x) = (x-2)/x, the limit as x approaches infinity is ALSO 1, and for the function f(x) = x/(x-1) the limit as x approaches infinity is .... 1. Obviously for any finite number they will not have the same value, but conceptually they all converge to the same value as you go to infinity. Hopefully this illustrates why you cannot apply the concept of rational vs irrational to "infinity".
Any number with a defined end point, including 2.14, is a rational number.
As written, it is a terminating decimal, which can be converted to a quotient(fraction) . Hence it is rational. However, if 0.678667866678.... then it is recurring to infinity . , Since it will not convert to a quotient/fraction , then it is irrational.
Any number with a defined end-point, such as -0.4744, is rational.
4.6 is rational.
is 34.54 and irrational or rational. number
Next to any rational number is an irrational number, but next to an irrational number can be either a rational number or an irrational number, but it is infinitely more likely to be an irrational number (as between any two rational numbers are an infinity of irrational numbers).
No. It is not defined if the rational number happens to be 0.
Because irrational numbers are defined as all real numbers which are not rational.
Because irrational numbers are defined as real numbers which are not rational.
It is irrational - unless the divisor is 0 in which case the division is not defined.
No. There are infinitely many of both but the number of irrational numbers is an order of infinity greater than that for rational numbers.
Any number with a defined end point, including 2.14, is a rational number.
No. The intersection of the two sets is null. Irrational numbers are defined as real numbers that are NOT rational.
Yes, fewer by an order of infinity.
Most numbers with a defined endpoint are not irrational. Therefore, 1.33333333333 is not an irrational number, but 1.3 recurring is an irrational number.Ans. 21.3 recurring is not irrational. In general any decimal that has a repeated pattern that continues to infinity is rational.1.3 recurring is just 4/3.
As written, it is a terminating decimal, which can be converted to a quotient(fraction) . Hence it is rational. However, if 0.678667866678.... then it is recurring to infinity . , Since it will not convert to a quotient/fraction , then it is irrational.
No. If it is possible to write it out, then it is rational. (For example, 0.1435897488972049876329487678694743896787917934706982770398847689189083709387987209870928763891787385173986517632871463287659670234857209872894775 may seem irrational, but it IS possible to write it out completely so it is rational.)the square root of 2, and Pi, are both irrational because their values go into infinity, with no pattern.1/7 may seem irrational because it goes off to infinity, but it IS rational, because its numbers repeat. (0.142857142857142815142857........)