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The answer is exponential and arrays in two dimensions as follows:

Dimension 1:

3.121

3.1211

3.12111

3.121111... and so on to infinity

Dimension 2:

3.121n

3.122n

3.123n

3.124n

3.125n

3.126n

3.127n

3.128n

3.129n

Where n = 1 to 9 for every additional decimal point you add.

In short, there's an infinite amount of numbers between 3.12 and 3.13

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3.125

Q: Can you find a number between 3.12 and 3.13?

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Either 313 or 312 are correct as 312.5 is halfway between either number.

It is 313 because .9 is greater than .5

It lies between the cube roots of 311 and 313.

It is 313 - 178 = 135

It is 313 - 178 = 135.

Finding divisibility by 3 and 9 are very easy to do. Simply add up the digits in the number and see if they are divisible by the number you are looking for. 3+1+3=7 and 7 is not divisible by 3, is 313 is not either. ◄ 3+1+2=6 and 6 is divisible by 3, so 312 is also. 312/3=104

312 + 313= 625, anything really fat like people(:

8

1 and 313 (313 is a prime number).

313 is a prime number.

313 is a prime number.

1 and 313 - It is a prime number.