The answer is exponential and arrays in two dimensions as follows:
Dimension 1:
3.121
3.1211
3.12111
3.121111... and so on to infinity
Dimension 2:
3.121n
3.122n
3.123n
3.124n
3.125n
3.126n
3.127n
3.128n
3.129n
Where n = 1 to 9 for every additional decimal point you add.
In short, there's an infinite amount of numbers between 3.12 and 3.13
It is 313 because .9 is greater than .5
The number 313 is a prime number, which means it is only divisible by 1 and itself. Therefore, the prime factorization of 313 is simply 313 x 1. Prime factorization is the process of breaking down a number into its prime factors, but since 313 is already a prime number, it cannot be further factored.
yes
3.026 = 313/500
3.52 = 313/25
Either 313 or 312 are correct as 312.5 is halfway between either number.
It is 313 because .9 is greater than .5
It lies between the cube roots of 311 and 313.
It is 313 - 178 = 135
It is 313 - 178 = 135.
Finding divisibility by 3 and 9 are very easy to do. Simply add up the digits in the number and see if they are divisible by the number you are looking for. 3+1+3=7 and 7 is not divisible by 3, is 313 is not either. ◄ 3+1+2=6 and 6 is divisible by 3, so 312 is also. 312/3=104
8
1 and 313 (313 is a prime number).
1 and 313 - It is a prime number.
313 is a prime number.
The number 313 is a prime number, which means it is only divisible by 1 and itself. Therefore, the prime factorization of 313 is simply 313 x 1. Prime factorization is the process of breaking down a number into its prime factors, but since 313 is already a prime number, it cannot be further factored.
313 - 178 = 135