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Q: Could three consecutive whole numbers all be prime numbers?

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There is only one pair of consecutive prime numbers, and the prime numbers are two and three, because any pair of consecutive numbers has one odd and one even number, and two is the only even prime number, because all other even numbers can be divided by two, and the only pairs of consecutive numbers are one and two and three, but one is not prime because it only has one factor, thus making the only consecutive pair of primes two and three. But the problem asks for the product of the two numbers, not the numbers themselves, so just multiply two and three together to get a final result of six.

After (3, 5, 7), you can't have any more such "triplets", since one of the three must needs be a multiple of 3.

There are no three consecutive numbers with a sum of 170.

125, 126 and 127.

The numbers are 59, 60 and 61.

Related questions

Yes 1 2 and 3 are consecutive and prime

The three consecutive odd prime numbers are 3, 5, and 7.

3, 5 and 7 are consecutive odd prime numbers.

No other prime numbers are consecutive because there aren't any other even prime numbers.

Yes but the on prime numbers are 2,3

If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.

Only 1 2 3

2, 3Those two are consecutive, natural and prime numbers! It's as easy as one, two, three! (Pun intended)

There is only one pair of consecutive prime numbers, and the prime numbers are two and three, because any pair of consecutive numbers has one odd and one even number, and two is the only even prime number, because all other even numbers can be divided by two, and the only pairs of consecutive numbers are one and two and three, but one is not prime because it only has one factor, thus making the only consecutive pair of primes two and three. But the problem asks for the product of the two numbers, not the numbers themselves, so just multiply two and three together to get a final result of six.

As the number 1 is considered a special case and not a prime, there cannot be three consecutive numbers that are prime. Any three consecutive numbers must include at least one even number. With the exception of the number 2, no even numbers are prime.

No. Any three consecutive numbers will have at least one of them which is divisible by 2, which means it cannot be prime. And since 1 is not considered a prime number, it cannot happen.

After (3, 5, 7), you can't have any more such "triplets", since one of the three must needs be a multiple of 3.

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