Yes, well, up to 97 actually.
472.
33 x 3 = 99
It will round up, as it ends with a 99 to give 6000 as the answer.
101103107109113127131137139149151157163167173179181191193197199
You need to add all the numbers from 10 to 99. You can do that quickly with the formula for an arithmetic series.
YES, though i'm not positive.
🤷‍♀️
Just 47.
472.
There is just one group: 2 and 3. No other primes are consecutive.
Two numbers are said to be co-prime if their only common factor is 1 or their GCF is 1. 90 and 99 share 1, 3 and 9 as their common factors so 90 and 99 are not co-prime.
A number divisible by 99 is any integer that can be expressed as (99n), where (n) is an integer. For example, 198 (which is (99 \times 2)) and 297 (which is (99 \times 3)) are both divisible by 99. The key characteristic of these numbers is that they must meet the divisibility rule for both 9 and 11, since 99 is the product of these two primes.
11 times 9 gives you 99
The LCM of 99, 456 & 867 is 3 99 = 32 x 11 456 = 23 x 3 x 19 867 = 3 x 172 LCM = lowest power of the common primes of the factorisations multiplied together ⇒ LCM = 3
Oh, dude, you want me to do math now? Fine, fine. So, the two-digit primes that are greater than 12 but less than 99 and still prime when you swap their digits are 13, 17, 31, 37, 71, 73, 79, and 97. Add them up and you get 398. Math is fun, right?
33 x 3 = 99
All multiples of 99 are divisible by 99