To find the HCF of 36 and 66 you first need to express them as a product of their prime factors: 36 = 2x2x3x3 66 = 2x3x11 The next step is to identify any common prime factors. In this case, both numbers have a 2 and a 3 as prime factors. Multiply these together, and you get: 2x3 = 6 Thus the hcf of 36 and 66 is 6.
To express 72 as a product of its prime factors, we first identify the prime numbers that can divide evenly into 72. We start by dividing 72 by the smallest prime number, 2, which gives us 36. Then, we divide 36 by 2 again to get 18. Next, we divide 18 by 2 to get 9. Finally, we divide 9 by 3 to get 3. Therefore, the prime factors of 72 are 2 x 2 x 2 x 3 x 3.
As a product of its prime factors: 2*2*2*2*2 = 36 or in exponents 2^5 = 36
36 = 22 x 32
As a product of its prime factors in exponents: 22*38 = 26244
It is: 2*2*3*3 = 36
36 as a product of its prime factors is 2 x 2 x 3 x 3. Their total is 10. 36 as a product of factors that total 13 is 4 x 9
The prime factors of 36 are 2, 2, 3, and 3, so their product is 36. The distinct prime factors of 36 are 2 and 3, so their product is 6.
As a product of its prime factors: 2*2*3*3 = 36
As a product of its prime factors in exponents: 22*32 = 36
As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39
As a product of its prime factors it is: 223*3 = 36
As a product of its prime factors in exponents: 22*32 = 36
As a product of its prime factors: 2*2*3*3 = 36
That's usually as a product of its prime factors. Here's an example: 2 x 2 x 3 x 3 = 36
To find the HCF of 36 and 66 you first need to express them as a product of their prime factors: 36 = 2x2x3x3 66 = 2x3x11 The next step is to identify any common prime factors. In this case, both numbers have a 2 and a 3 as prime factors. Multiply these together, and you get: 2x3 = 6 Thus the hcf of 36 and 66 is 6.
As a product of its prime factors: 2*2*3*3 = 36