To express 540 as a product of prime factors, we need to find the prime numbers that multiply together to give 540. Start by dividing 540 by the smallest Prime number, which is 2. 540 ÷ 2 = 270. Then continue dividing by prime numbers until you reach the prime factorization of 540, which is 2 x 2 x 3 x 3 x 3 x 5. So, 540 can be expressed as 2^2 x 3^3 x 5.
2 x 2 x 3 x 3 x 3 x 5 or 22 x 33 x 5
Prime factorization: 540 = 2 x 270 = 2 x 2 x 135 = 2 x 2 x 3 x 45 = 2 x 2 x 3 x 3 x 15 = 2 x 2 x 3 x 3 x 3 x 5 540 as a product of its prime factors: 2x2x3x3x3x5
22 x 33 x 51
LCM of 90 and 108 is 540 The LCM is the product divided by the GCF 90 factors into [2 3 3 5] 108 factors to [2 2 3 3 3] common factors are [2 3 3] so GCF=18 90 * 108 / 18 = 540
factors of 540 are 1,2,3,4,5,6,9,10,12,15,18,20,27,30,36,45,54,60,90,108,135,180,270,540
Prime factorization of 540 = 2x2x3x3x3x5 Prime factorization of 80 = 2x2x2x2x5
As a product of its prime factors it is: 2*2*3*3*3*5 = 540 or as 22*33*5 =540
2 x 2 x 3 x 3 x 3 x 5 or 22 x 33 x 5
The prime factors of 540 are: 2, 3, 5 The prime factors of 1,008 are: 2, 3, 7
540 = 2 x 2 x 3 x 3 x 3 x 5
Prime factorization: 540 = 2 x 270 = 2 x 2 x 135 = 2 x 2 x 3 x 45 = 2 x 2 x 3 x 3 x 15 = 2 x 2 x 3 x 3 x 3 x 5 540 as a product of its prime factors: 2x2x3x3x3x5
2*2*3*3*3*5 = 540
The factors of 540 are: 1 2 3 4 5 6 9 10 12 15 18 20 27 30 36 45 54 60 90 108 135 180 270 540. The prime factors are: 2, 3 and 5
22 x 33 x 51
Composite. It has more than two factors.
It is a composite number because it has more than two factors
540 = 1 x 540 540 = 2 x 270 540 = 3 x 180 540 = 4 x 135 540 = 5 x 108 540 = 6 x 90 540 = 9 x 60 540 = 10 x 54 540 = 12 x 45 540 = 15 x 36 540 = 18 x 30 540 = 20 x 27