Perform an algorithmic decomposition of the integer 625 with the prime factorization method. Begin by noticing that 625 is a multiple of 5 because the units digit is 5. Thus, we have that 625 is the product of 5 and 125. Next, observe that 125 can also be broken down further into the product of 5 and further more until we notice that 5 raised to the fourth power is 625. There are no other integer factors of 625.
1, 5, 25, 125, 625
The factors of 625 are: 1 5 25 125 625The prime factor of 625 is: 5
The factors of 625 are: 1 5 25 125 625The prime factor is: 5
The factors of 625 are 1, 5, 25, 125, and 625.The prime factors of 625 are 5, 5, 5, and 5.The distinct prime factor of 625 is 5.The prime factorization of 625 is 5 x 5 x 5 x 5 or, in index form (in other words, using exponents), 54.1, 5, 25, 125, 625
1, 5, 25, 125, 625
5 x 5 x 5 x 5 = 625
The factors of 625 are: 1, 5, 25, 125, 625
Identify the prime factors of 625 which are : 5 x 5 x 5 x 5 = 625. The factors of 625 are therefore 1 x 625, 5 x 125 and 25 x 25. As the number 25 is effectively duplicated then 625 has 5 factors (1, 5, 25, 125 & 625)
The Common Factors of 625 and 120 are 1, 5
The factors of 625 are 1, 5, 25, 125, and 625
The factors of 625 are: 1 5 25 125 625The prime factor of 625 is: 5
16, 81, 256, 625 all have five factors.
The factors of 625 are: 1 5 25 125 625The prime factor is: 5
The factors of 625 are 1, 5, 25, 125, and 625.The prime factors of 625 are 5, 5, 5, and 5.The distinct prime factor of 625 is 5.The prime factorization of 625 is 5 x 5 x 5 x 5 or, in index form (in other words, using exponents), 54.1, 5, 25, 125, 625
1, 5, 25, 125, 625
625 125,5 25,5,5 5,5,5,5 54 = 625
As a power of its prime factors: 5^4 = 625
5 x 5 x 5 x 5 = 625