Use a factor tree. 400 200,2 100,2,2 50,2,2,2 25,2,2,2,2 5,5,2,2,2,2
24 x 52 = 400
find the prime factorization of 268
Prime factorization of 560 = 2x2x2x2x5x7.
The Highest Common Factor (HCF) of two numbers is the largest number that divides both numbers without leaving a remainder. To find the HCF of 120 and 400, you can use the prime factorization method. The prime factorization of 120 is 2^3 * 3 * 5 and the prime factorization of 400 is 2^4 * 5^2. To find the HCF, you take the common prime factors with the lowest exponent, which in this case is 2^3 * 5 = 40. Therefore, the HCF of 120 and 400 is 40.
Use a factor tree. 400 200,2 100,2,2 50,2,2,2 25,2,2,2,2 5,5,2,2,2,2
400 = 2^4 × 5^2
The prime factorization of 400 is 2x2x2x2x5x5 (or 24 x 52 in exponential form).
The prime numbers (factors) of 400 are: 2 and 5
24 x 52 = 400
find the prime factorization of 268
The last prime before 400 is 397.The prime factorization of 400 is 2x2x2x2x5x5.
You can't. You can only find the prime factorization of an integer.
find the prime factorization to the number 81
Prime factorization of 560 = 2x2x2x2x5x7.
The prime factorization of 15332 • 17153 is not a prime number
The Highest Common Factor (HCF) of two numbers is the largest number that divides both numbers without leaving a remainder. To find the HCF of 120 and 400, you can use the prime factorization method. The prime factorization of 120 is 2^3 * 3 * 5 and the prime factorization of 400 is 2^4 * 5^2. To find the HCF, you take the common prime factors with the lowest exponent, which in this case is 2^3 * 5 = 40. Therefore, the HCF of 120 and 400 is 40.