Pair 1: (3 and 5) LCM = 15
Pair 2: (3 and 7) LCM = 21
Pair 3: (13 and 19) LCM = 247
16 and 25 23 and 47 27 and 50
If the product of three numbers is 140, then we can write 140 as aXbXc. Let a be 10 and let b be 2. Then 140 equals 10X2Xc, or 7 equals c. Thus, the remaining number is 7.
5 * 17 * 23 =1955
It is the product of 2,5, and 7
15 is the product of two prime numbers; 3 x 5
Pick pairs of prime numbers. Pick any pairs of prime numbers.
It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25
5 and 7 8 and 17 22 and 25
14 and 25 36 and 49 5 and 7
16 and 25 23 and 47 27 and 50
Any pair of prime or relatively prime numbers.25 and 367 and 1113 and 19
If the product of three numbers is 140, then we can write 140 as aXbXc. Let a be 10 and let b be 2. Then 140 equals 10X2Xc, or 7 equals c. Thus, the remaining number is 7.
Select any two numbers that are coprime: that is they do not have any factor in common. For example, 7 and 13, or 14 and 39, or 8 and 27
5 x 17 x 23
Three pairs of integers alone have this property: 12 and 1; 2 and 6; and 3 and 4. There are infinitely many non-integer pairs also.
As a product of its prime factors: 7*29*37 = 7511
5 * 17 * 23 =1955