Q: Find three pairs of numbers for which the LCM equals the product of the two numbers?

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16 and 25 23 and 47 27 and 50

If the product of three numbers is 140, then we can write 140 as aXbXc. Let a be 10 and let b be 2. Then 140 equals 10X2Xc, or 7 equals c. Thus, the remaining number is 7.

5 * 17 * 23 =1955

It is the product of 2,5, and 7

15 is the product of two prime numbers; 3 x 5

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It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25

5 and 7 8 and 17 22 and 25

14 and 25 36 and 49 5 and 7

16 and 25 23 and 47 27 and 50

If the product of three numbers is 140, then we can write 140 as aXbXc. Let a be 10 and let b be 2. Then 140 equals 10X2Xc, or 7 equals c. Thus, the remaining number is 7.

Select any two numbers that are coprime: that is they do not have any factor in common. For example, 7 and 13, or 14 and 39, or 8 and 27

5 x 17 x 23

Three pairs of integers alone have this property: 12 and 1; 2 and 6; and 3 and 4. There are infinitely many non-integer pairs also.

it is 7yx978

5 * 17 * 23 =1955

As a product of its prime factors: 7*29*37 = 7511

The product. Of three negative numbers is negative I hope you can get 100 in your homework