16 and 25 23 and 47 27 and 50
If the product of three numbers is 140, then we can write 140 as aXbXc. Let a be 10 and let b be 2. Then 140 equals 10X2Xc, or 7 equals c. Thus, the remaining number is 7.
5 * 17 * 23 =1955
It is the product of 2,5, and 7
15 is the product of two prime numbers; 3 x 5
It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25
5 and 7 8 and 17 22 and 25
14 and 25 36 and 49 5 and 7
16 and 25 23 and 47 27 and 50
If the product of three numbers is 140, then we can write 140 as aXbXc. Let a be 10 and let b be 2. Then 140 equals 10X2Xc, or 7 equals c. Thus, the remaining number is 7.
Select any two numbers that are coprime: that is they do not have any factor in common. For example, 7 and 13, or 14 and 39, or 8 and 27
5 x 17 x 23
Three pairs of integers alone have this property: 12 and 1; 2 and 6; and 3 and 4. There are infinitely many non-integer pairs also.
it is 7yx978
5 * 17 * 23 =1955
As a product of its prime factors: 7*29*37 = 7511
The product. Of three negative numbers is negative I hope you can get 100 in your homework