Best Answer

-13*-14 = 182

Lvl 1

-13x-14=182

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Lvl 3

-14 and -13.

Q: Find two consecutive negative integers whose product is 182?

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There are no two consecutive integers, negative or positive, whose product is 440.

There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.

They are: 40*41 = 1640

11 and 13

I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.

Related questions

There are no two consecutive integers, negative or positive, whose product is 440.

-8 -9

-10 -11

There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.

-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.

The two consecutive positive integers whose product is 380 are 19 x 20.

The product of two integers cannot be "positive and negative".

The integers are -12, -10 and -8.

the two consecutive positive integers whose product is 380 19 20

There is no solution.Consecutive negative integers will always add up to a negative number. 110 is positive.

The integers are -6, -5 and -4 OR -7, -5 and -3 using only consecutive odd integers.

The two consecutive, odd integers whose product equals 143 are 11 and 13.