We note that 8 = 4 x 2'
So 4 x 7 = 28
So mulktply 28 by '2'
Hence 28 x 2 = 56 The answer!!!!!
63
4 x 578 = 2312 8 x 754 = 6032
2(4 x 7)
The two numbers are either 7 and 8 or -7 and -8.
The easiest way of both number are even, is to keep halving them both until one of them becomes odd: 4/28 = 2/14 = 1/7 Otherwise you use the times tables to find out what both will divide into evenly 4 x 1 = 4 4 x 7 = 28 = 1/7
you can muit by 4s and 8s.
since 4 is 2 times 2 just double 7 twice: 7 doubled = 14 and then 14 double = 28
(7 x 10) + (7 x 4) + (7 x 0.6) = 70 + 28 + 4.2 = 102.2
Product means multiply Therefore the product of 4 and 7: 4 x 7 = 28
To find the product of 4 over 7 (4/7) and 56, you simply multiply the two numbers together. This can be done by multiplying the numerators (4 * 56) and the denominators (7 * 1) separately. Therefore, the product of 4/7 and 56 is (4 * 56) over (7 * 1), which simplifies to 224 over 7 or 32.
4/5.6/7
4 times 7 = 28 2( 4 times 7 ) = 2 times 28 = 56. I hoped I helped. XOXO W T F you don't know :(
Probably 2*3*4*5*6*7 = 5040
(7x4) + (4x7) = 28 + 28 = 56
Product = Multiplication 273 X 7 = 1911
63
Their product.