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x-y = 5; x/y = 5; solve x = 5y; substitute 5y-y = 5;4y=5; y =5/4 and x = 25/4

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6y ago
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6y ago

The two numbers are 25/6 and 5/6.

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6y ago

25/4, 5/4

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Q: How do I find Find two numbers whose difference and whose quotient are each equal to five?
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