How do you convert decimal 98 to an 8-bit binary value?

Answer 1

You convert 98 base 10 into 1100010 base 2 the same way you convert any decimal number into a binary number. You iteratively divide by 2, recording the remainders in reverse order, until the quotient is zero.

98 / 2 = 49 remainder 0

49 / 2 = 24 remainder 1

24 / 2 = 12 remainder 0

12 / 2 = 6 remainder 0

6 / 2 = 3 remainder 0

3 / 2 = 1 remainder 1

1 / 2 = 0 remainder 1

So the result, reading backwards (up) is 1100010 base 2.

and as an 8 bit value it would be 01100010.

The more general answer is that, to convert a number in any base to any other base, iteratively divide the first number by the second base, using the rules of arithmetic of the first base, recording the remainders in reverse order, until the quotient is zero. The remainders then need to be written in terms of the second base.