There's a dilutionfactor of 70/96=0.729, when you make 1 liter, you have to use 729 milliliters of ethanol, then you to add water till 1 liter total.
First calculate how much ethanol you need in the final solution. 55% X 2.5l = 1.375l Then calculate how much ethanol you already have in the solution. 0.5l X 70% = 0.35l Now take the difference between those two numbers as the extra amount needed. 1.375l - 0.35l = 1.025l Now correct for the fact that you are adding only 96% ethanol. 1.025l / 96% = 1.068l Answer: 1.068l
70% of 96= 70% * 96= 0.7 * 96= 67.2
7 gram elemental iodine and 93 gram 'ethanol in water' mixture (70% - 96%)
Disinfectants are usually mostly alcohol, Ethanol to be exact. Ethanol can only reach a purity degree of 95-96 percent in liquid form, with purer solutions existing only as a gas. 70 percent alcohol is sufficient to kill the bacteria, and a higher purity would not have any beneficial effect.
96 dollars - 30% = 70% of 96 dollars = 96*70/100 = 67.20 dollars.
Approximately 96%.
320-96= 224?
Leaves a balance of 96
Leaves a balance of 96
120% of 80 = 96 80% of 120 = 96 70% of 150 = 105 150% of 200 = 300 200% of 150 = 300
It's just multiplication. 70 percent of your total will be 85 20 percent of your total will be 75 10 percent of your total will be 96 (85 x 0.70) + (75 x 0.25) + (96 x 0.10) = YOUR GRADE AVERAGE
A 99% solution of alcohol will self-dilute by absorbing moisture from the atmosphere unless completely sealed.