2^4 x 3 x 5
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
120 = 23 x 3 x 5
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
Prime factors of 1080 are 23 33 5.
As a product of its prime factors: 2*3*3*5 = 90
It is: 24*112 = 1936
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
120 = 23 x 3 x 5
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
To express 144 as a product of its prime factors in index form, we first find the prime factors of 144, which are 2 and 3. 144 can be written as 2^4 * 3^2 in index form, where 2 is raised to the power of 4 and 3 is raised to the power of 2. This shows that 144 can be expressed as the product of its prime factors in index form.
To express 600 as a product of prime numbers in index form, we first factor 600 into its prime components. The prime factorization of 600 is (600 = 2^3 \times 3^1 \times 5^2). This means 600 can be expressed as the product of its prime factors: (2^3 \times 3^1 \times 5^2).
Prime factors of 1080 are 23 33 5.
express 5610 as the product of prime factors
As a product of its prime factors: 2*3*3*5 = 90
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
As a product of its prime factors: 2*3*5*7 = 210
300