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In the above question, there is no symbol before 5v.
a proper factor is a factor.
a factor bug is a factor
A composite factor is a factor that is a composite number, as opposed to a prime factor which is a factor that is a prime number.
If it does not factor properly then you cannot factor it.
Factors are divisors. A factor times a factor will equal a product.
(6r - 7v)(3r - 2v)
(v + 2)(v^2 - 2v + 4)
100 V2 - 25 W2 = (10V + 5W) (10V - 5W)Another way to show it:100 V2 - 25 W2 = 25 (4 V2 - W2) = 25 (2V - W) (2V + W)
v^6 -64 = (v - 2)(v + 2)(v^2 - 2v + 4)(v^2 + 2v + 4)
When the speed of an object doubles, its kinetic energy increases by a factor of four. This is because kinetic energy is directly proportional to the square of the speed of an object. Therefore, if the speed doubles, the kinetic energy will increase by a factor of two squared, which is four times the original kinetic energy.
the output of 7805 is 2v or 3v if we give the input as 2v or 3v.
Do you mean 1400v + 2v^7 (is 2v to the power 7)? When you differentiate, e.g. 2v^7, you bring the 7 to the front and reduce the power by 1. If so the answer is 1400 + 7*2v^6 (where * means multiply) or 1400 + 14v^6
2v
Vp=2 Vdc=50 r=Vrms/Vdc Vrms=Vp/1.121 so r=0.028
It is equivalent to: 35-14v
Clipping level increases. For example, if the clipping level was 2V before freezing, it will clip at a voltage greater than 2V when frozen.
v=5