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In the above question, there is no symbol before 5v.
a proper factor is a factor.
a factor bug is a factor
A composite factor is a factor that is a composite number, as opposed to a prime factor which is a factor that is a prime number.
If it does not factor properly then you cannot factor it.
Factors are divisors. A factor times a factor will equal a product.
(6r - 7v)(3r - 2v)
(v + 2)(v^2 - 2v + 4)
100 V2 - 25 W2 = (10V + 5W) (10V - 5W)Another way to show it:100 V2 - 25 W2 = 25 (4 V2 - W2) = 25 (2V - W) (2V + W)
v^6 -64 = (v - 2)(v + 2)(v^2 - 2v + 4)(v^2 + 2v + 4)
the output of 7805 is 2v or 3v if we give the input as 2v or 3v.
Do you mean 1400v + 2v^7 (is 2v to the power 7)? When you differentiate, e.g. 2v^7, you bring the 7 to the front and reduce the power by 1. If so the answer is 1400 + 7*2v^6 (where * means multiply) or 1400 + 14v^6
Kinetic energy at velocity "V" is (0.5) x mass x V x V Kinetic energy at velocity "2V" is (0.5) x mass x 2V x 2V Ratio of KE at velocity 2V and KE at velocity V is [(0.5) x mass x 2V x 2V] / [(0.5) x mass x V x V] = 4 So if the velocity double, KE quadruples
2v
Vp=2 Vdc=50 r=Vrms/Vdc Vrms=Vp/1.121 so r=0.028
It is equivalent to: 35-14v
Clipping level increases. For example, if the clipping level was 2V before freezing, it will clip at a voltage greater than 2V when frozen.
You will have to call Browning to find out.