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More answers

a8 - b8 = ((a4)2 - (b4)2) [the difference of two squares]

= (a4 + b4)(a4 - b4)

= (a4 + b4)(a2 + b2)(a2 - b2)

= (a4 + b4)(a2 + b2)(a + b)(a -b)

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Wiki User

12y ago
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This is the answer of question

a8-b8

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Atiq Rehman

Lvl 2
4y ago
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(a^4)^2-(a^4)^2

(a^4+b^4) (a^4-b^4)

(a^4+b^4) (a^2)^2- (b^2)^2

(a^4+b^4). (a^2+b^2) (a^2-b^2)

(a^4+b^4). (a^2+b^2) (a+b) (a-b)

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Q: How do you factor a8-b8 completely?
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