How do you factor a8-b8 completely?

Answer 1

0

Answer 2

a8 - b8 = ((a4)2 - (b4)2) [the difference of two squares]

= (a4 + b4)(a4 - b4)

= (a4 + b4)(a2 + b2)(a2 - b2)

= (a4 + b4)(a2 + b2)(a + b)(a -b)

Answer 3

This is the answer of question

a8-b8

Answer 4

a^(8) - b^*8( =

(a^(4) - b^(4))((a^(4) + b^(4))

[a^(2) - b^(2)][a^(2 + b^(2)](a^(4) + b^(4))

{a - b}{a + b}][a^(2) + b^(2)](a^(4) + b^(4))

Fully factored.

NB Different shaped brackets are only for clarity.

NNB Squared term / Even numbered indices with a positive (+) between then do NOT factor.

Answer 5

(a^4)^2-(a^4)^2

(a^4+b^4) (a^4-b^4)

(a^4+b^4) (a^2)^2- (b^2)^2

(a^4+b^4). (a^2+b^2) (a^2-b^2)

(a^4+b^4). (a^2+b^2) (a+b) (a-b)