a8 - b8 = ((a4)2 - (b4)2) [the difference of two squares]
= (a4 + b4)(a4 - b4)
= (a4 + b4)(a2 + b2)(a2 - b2)
= (a4 + b4)(a2 + b2)(a + b)(a -b)
This is the answer of question
a8-b8
(a^4)^2-(a^4)^2
(a^4+b^4) (a^4-b^4)
(a^4+b^4) (a^2)^2- (b^2)^2
(a^4+b^4). (a^2+b^2) (a^2-b^2)
(a^4+b^4). (a^2+b^2) (a+b) (a-b)
6a squared-8ab+2a factor completely and check mentally
there always is one-every # has the factor 1 hint:)
Completely factor the expression by grouping 50cp-4wz+5pw-40cz
factor completely 6t^3 - 8t^2 - 30t
Factor completely and check mentally 10a^2+20a
It is an algebraic factor.
10a * (a + 2)
(a - 7b)(a + 6b)
3 * x * x * y
b(b - 8)
7(y + 4)
12n2 plus 8n?