To find the smallest number that has 1, 2, 3, 4 and 5 as factors, you're looking for the least common multiple, or LCM, of those numbers. You can find that by listing the multiples of each number but it's faster to combine their prime factors. You need two twos, a three and a five.
2 x 2 x 3 x 5 = 60
60
Multiples of 60
2,3,4,5,6,10,12,15,20,30
Every one of them has an even number of factors.
Prime factors of 60 are: 2, 3 and 5 Prime factors of 70 are: 2, 5 and 7
60
One possible answer is "factorial".
The answer is 60
Any multiple of 60.
60 has more factors than 100 does.
Any multiple of 60.
Any prime number to the 59th power will have 60 factors.
To express the number 60 as a product of prime factors, we need to break it down into its prime factors. First, we divide 60 by the smallest prime number, which is 2. This gives us 2 x 30. Next, we divide 30 by 2, giving us 2 x 2 x 15. Finally, we divide 15 by 3, resulting in 2 x 2 x 3 x 5. Therefore, the prime factorization of 60 is 2 x 2 x 3 x 5.
60 is a composite number. 60 has integer factors other than itself and 1.
Multiples of 60
2,3,4,5,6,10,12,15,20,30
60