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Lets try z^-1 which is 1/z. Now z=x+iy then 1/z = 1/(x+iy). This is equal to
(x-iy)/((x+iy)(x-iy)) and is equal to (x-iy)/(xx+yy). The real part is u=x/(xx+yy) and the imaginary part is -y/(xx+yy). Don't forget that i squared is -1 when working out (x+iy)(x-iy). Get a good program like Mathmatica as higher exponents get real time consuming and will cause brain damage!
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How do you simplify negative numbers with positive exponents?
If the exponent is an even number you can drop the negative, because is you were to multiply it out the negatives would cancel out.
Is -7 a complex number?
Yes, all real numbers are complex numbers.
What happens when you square root a negative number?
The square root of a negative number is not real. However, there is a field of numbers known as the complex number field which contains the reals and in which negative numbers have square roots. Complex numbers can all be expressed in the form a+bi where a and b are real and i is the pure imaginary such that i2=1. Please see the related links for more information about complex and imaginary numbers.
How do you simplify complex numbers?
Hi, See the related answers and the Related Link. My friends are working hard to supply more answers.
What are non-zero real numbers?
Non-Zero Real Numbers are infact complex conjugate numbers. They are negative prime numbers.
