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i25 · Step 1. 25÷ 4 has a remainder of 1 · Step 2. i25 = i1=i Rule : i4 is equal to 1 apply the following formula to reduce i to any power just divide the given power by 4 and then whatever you get as the remainder just put it as the power of i in your answer ik = ir Where r = the remainder of k÷4 And then solve it like i1 would be i or i2 would be -1 or i3 would be -i and so on. Other Example: i9 § Step 1. 9 ÷ 4 has a remainder of 1 § Step 2. i9 = i1 i103 § Step 1. 103 ÷ 4 has a remainder of 3 § Step 2. i103 = i3 = -i
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What are the roots of complex numbers in mathematics?
See the answer to the related question: 'How do you solve the power of an imaginary number?' (Link below)
Can you divide an imaginary number by a real number?
an imaginary number is imaginary so no (i guess) this answer kind of sucks
Can a no real number be a pure imaginary number?
If a number is pure imaginary then it has no real component. If it is a real number, then there is no imaginary component. If it has both real and imaginary components, then it is a complex number.
How do you simplify the imaginary number -125?
-125 is NOT an imaginary number.
Whats an imaginary number?
An imaginary number is a number that has the square root of -1 as one of its factors.
