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Q: How do you write each expression as a product of its factors?

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9x4 = 32*x4 has (2+1)*(4+1) = 3*5 = 15 different factors. When an expression is written out as the product of its prime factors in index form, the number of factors can be calculated as the product of each index increased by one.

You factor the number into prime factors, dividing each prime out.

Numerators and denominators are just numbers. List the factors of each and circle the numbers that appear on both lists. These are common factors.

No - because its factors include each of the two prime numbers.

The number of decimal places for the product will be the summation of the amount of decimal places of the 2 factors. For example, if your products have 2 decimals each to the right of zero then the product will have an answer with 4 decimals to the right of zero.

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10001/999900

It is: 3*29 = 87

a-n = 1/an = (1/a) x .... x (1/a), this last product having n factors, each is 1/a

Write the general algebraic expression for each using matchstick?

9x4 = 32*x4 has (2+1)*(4+1) = 3*5 = 15 different factors. When an expression is written out as the product of its prime factors in index form, the number of factors can be calculated as the product of each index increased by one.

For each of a list of algebraic expressions, find one or more common factors and factorise the expression.

Read the problem. Write each fact as a variable expression. Write each fact as a sentence.

Two numbers are factors of a product when they multiply with each other to become the product. For example, if the product number is 10, then our factors can be 2 and 5, or 1 and 10.

the + of a number and 10 k decreased by 4 = k-4

12 can be written as 3 x 4 or 2 x 6

The product of a number of factors can be zero only if one of them is zero.So, if a given expression is zero, you factorise it and then, by the above rule, the statement is true if any one of the factors is zero. You therefore set each factor equal to zero to find the different possible solutions.

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