147abc = 3 x 7 x 7 x a x b x c
Basically, you use prime factorization x variables.
You factor the number into prime factors, dividing each prime out.
Numerators and denominators are just numbers. List the factors of each and circle the numbers that appear on both lists. These are common factors.
The number of decimal places for the product will be the summation of the amount of decimal places of the 2 factors. For example, if your products have 2 decimals each to the right of zero then the product will have an answer with 4 decimals to the right of zero.
No - because its factors include each of the two prime numbers.
The product will be greater than 1, when each of the two factors are greater than 1.
yes
10001/999900
a-n = 1/an = (1/a) x .... x (1/a), this last product having n factors, each is 1/a
Write the general algebraic expression for each using matchstick?
To factor a polynomial expression, you identify common factors among the terms and express the polynomial as a product of simpler polynomials. For example, consider the polynomial ( x^2 - 5x + 6 ); it factors into ( (x - 2)(x - 3) ). Each factor is written in descending order, starting with the highest degree term. The specific steps to factor will depend on the polynomial you are working with.
The algebraic expression for the product of 6 and s is 6s. In algebra, when two quantities are multiplied, we simply write them next to each other with no operation symbol in between. Therefore, 6 multiplied by s is represented as 6s.
Read the problem. Write each fact as a variable expression. Write each fact as a sentence.
For each of a list of algebraic expressions, find one or more common factors and factorise the expression.
the + of a number and 10 k decreased by 4 = k-4
To write 87 as a product of its prime factors, we first divide it by the smallest prime number, which is 3. This gives us 87 = 3 * 29. Since 29 is a prime number itself, the prime factorization of 87 is 3 * 29.
To write the expression (2 \times 2 \times 3 \times 3 \times 5 \times 5) using indices, you group the identical factors together. This gives you (2^2 \times 3^2 \times 5^2). Each base number is raised to the power of the number of times it appears in the product.
12 can be written as 3 x 4 or 2 x 6