Q: How do you write the prime factorization of 1323 exponential form?

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They are: 3*3*3*7*7 = 1323

33 x 72 = 1323

2646 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 24 factors of 2646 are 1, 2, 3, 6, 7, 9, 14, 18, 21, 27, 42, 49, 54, 63, 98, 126, 147, 189, 294, 378, 441, 882, 1323, and 2646.The proper factors of 2646 are 1, 2, 3, 6, 7, 9, 14, 18, 21, 27, 42, 49, 54, 63, 98, 126, 147, 189, 294, 378, 441, 882, and 1323 or,if the definition you are using excludes 1, they are 2, 3, 6, 7, 9, 14, 18, 21, 27, 42, 49, 54, 63, 98, 126, 147, 189, 294, 378, 441, 882, and 1323.The prime factors of 2646 are 2, 3, 3, 3, 7, and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The 3 distinct prime factors (listing each prime factor only once) of 2646 are 2, 3, and 7.The prime factorization of 2646 is 2 x 3 x 3 x 3 x 7 x 7 or, in index form (in other words, using exponents), 2 x 33 x 72.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.

The factors of 3969 are: 1, 3, 7, 9, 21, 27, 49, 63, 63, 81, 147, 189, 441, 567, 1323, and 3969.The prime factors of 3969 are: 3 and 7.

The LCM of 27 and 49 is 1323.

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They are: 3*3*3*7*7 = 1323

33 x 72 = 1323

The prime factorization of 1323 is 3 x 3 x 3 x 7 x 7

As a product of its prime factors: 3*3*3*7*7 = 1323

you find the prime factorization of 1008 and 1323 the find the numbers that match that are above each other or across the multiply all of them then you are done

The Prime Factors are: 3 x 3 x 3 x 7 x 7

1,323 =1.323 × 103or1.323E3

1323 is not prime. 1323 = 3 * 3 * 3 * 7 * 7

3 x 3 x 3 x 7 x 73^3 x 7^2

3 x 3 x 3 x 7 x 7

3 x 3 x 3 x 7 x 7 = 1323

Use a factor tree. 1323 441,3 147,3,3 49,3,3,3 7,7,3,3,3