53 bytes long
Memory dump which are in binary numbers would have many numbers of 0s and 1s. working with these numbers would be very difficult. Hence two number system hexadecimal and octal number system is used because these numbers are inter convertible with binary numbers by the concept of bits.
There are 16 symbols.
The ANSWER is 4
There are 168 = 4,294,967,296 such numbers.
How many bytes are there in a longword? How to turn hexadecimal CABBAGE4U into a single binary longword?
Used for what???The hexadecimal system is just a way to represent information. Each byte requires two hexadecimal digits. Modern computers have billions of bytes in RAM, and often a trillion or more bytes on the hard disk, so that would be billions or trillions of hexadecimal digits. Some examples of things that are often represented as hex digits: * An IPv6 address has 16 bytes - so, 32 hex digits. * A MAC address has 6 bytes (12 hex digits). * A register has a few bytes. The size varies, but is often 2-8 bytes.
Used for what???The hexadecimal system is just a way to represent information. Each byte requires two hexadecimal digits. Modern computers have billions of bytes in RAM, and often a trillion or more bytes on the hard disk, so that would be billions or trillions of hexadecimal digits. Some examples of things that are often represented as hex digits: * An IPv6 address has 16 bytes - so, 32 hex digits. * A MAC address has 6 bytes (12 hex digits). * A register has a few bytes. The size varies, but is often 2-8 bytes.
8 in octal, 16 in hexadecimal.
how many bytes are there in a 64-bit machine? Another Answer: It takes 8 bytes to store a 64 bit number.
how many bytes are there in a 64-bit machine? Another Answer: It takes 8 bytes to store a 64 bit number.
Considering the lowest five digit hexadecimal number is 10000 (65,536) and the highest is FFFFF (1,048,575), there are 983,040 different hexadecimal numbers that are five digits.
A "hextet" in IPv6 consists of 2 bytes, or 4 hexadecimal digits (as in the example in the question), or 16 bits.
FA2B = 2 bytes = 4 nibbles = 16 bits 1 1 1 1 . 1 0 1 0 . . . 0 0 1 0 . 1 0 1 1
4
The hexadecimal system is base 16.
In actual size there are 1024 byte in a kilobyte. and 1024 kb in a megabyte. So 1024 bytes times 1024 kb would equal the number of bytes in a megabyte 1,048,576 bytes. Then multiply that by the number of megabytes being 700 in this case to get 734,003,200 bytes in 700 megabytes. Dznytoy