194*114*25 = (2*97)(2*3*19)(5*5) so factors are 2, 3, 5, 19, 97 so it has 5 factors.
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No. Look at the following examples: The prime factors of 36 are 2, 2, 3, and 3. The prime factors of 62 are 2 and 31. The prime factors of 155 are 5 and 31. The prime factors of 168 are 2, 2, 2, 3, and 7. The prime factors of 194 are 2 and 97. The prime factor of 197 is 197.
2 has two factors.
194 2 x 97 Since both 2 and 97 are prime numbers, the prime factorization tree is complete.
9312 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 24 factors of 9312 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96, 97, 194, 291, 388, 582, 776, 1164, 1552, 2328, 3104, 4656, and 9312 .The proper factors of 9312 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96, 97, 194, 291, 388, 582, 776, 1164, 1552, 2328, 3104, and 4656 or,if the definition you are using excludes 1, they are 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96, 97, 194, 291, 388, 582, 776, 1164, 1552, 2328, 3104, and 4656.The prime factors of 9312 are 2, 2, 2, 2, 2, 3, and 97. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The 3 distinct prime factors (listing each prime factor only once) of 9312 are 2, 3, and 97.The prime factorization of 9312 is 2 x 2 x 2 x 2 x 2 x 3 x 97 or, in index form (in other words, using exponents), 25 x 3 x 97.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
=3 factors=