without knowing the actual lengths of the shallow and deep ends, nothing more than a very loose ballpark number is possible.
10.2 US gallons.
1200 sf x 1 ft = 1200 cubic feet x 7.48 gallons/cf = 8976 gallons.
A hundred cubic feet, a unit of measure of water volume, usually encountered in water metering and billing, equivalent to 748 gallons.
About 200 feet.
how deep?
24,685.79 gallons
20000
If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.
10000000 gallons of water ;) it's true, my teacher told me
If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 21,722 gallons of water.
18,691.2 gallons if shallow end 4'
You need more information. But, let's assume the pool is 8 feet deep at the deep end and 3 feet at the shallow end. If the pool is rectangular, the total volume will be 28,798 gallons of water.
It really depends on the depth of the shallow end. However, let's say the shallow end is three feet deep. In that case, the pool holds up to about 22,980 gallons of water.
10,710. 10,710. The calculation for a rectangle pool is: ((Shallow end depth + deep end depth) / 2) * length * width) = pool volume in cubic feet Pool cubic feet * 7.5 = gallons of water the pool holds
Assuming the slope of the bottom is uniform, then the volume is 42979 Imperial gallons, approx.
10 feet
Assuming you mean the pool is 14 feet by 28 feet and has a shallow end of 4 feet and a deep end of 6 feet, then the total water volume would be approximately 14,700 gallons.