Q: How many integer between 3 and 74 are divisible by 5 with a remainder of 1?

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There are 89,999 numbers between 100,000 and 999,999 that are divisible by 10.

prime numbers between 0 -100 which are divisible by 7: 7

12. 13, if you count 200

How many positive integers between 100 and 999 inclusion, are divisible by 3 and 4?

There are 14 numbers between 1 & 100 that are divisible by 7.

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The divisor is missing. Please edit the question to include the relevant information.

2

They are: 210, 220, 230 and 240 which makes four of them

There are 10 numbers between 10 and 80 that are divisible by 7 with no remainder: 14, 21, 28, 35, 42, 49, 56, 63, 70, and 77.

All real numbers are divisible by 2. Only the even numbers (there are infinitely many) are divisible by 2 without remainder.

There are infinitely many numbers that are divisible by 202. They are all numbers of the form 202*k where k is some integer.

Eight: 45, 50, 55, 60, 65, 70, 75 and 80.

Counting up from 1, there is a number divisible by 3 every 3 numbers. Thus to find out how many numbers are divisible by 3, we just have to divide the number we're counting to by 3. In this case, the top number is 50, so do: 50/3 = 16 with two remainder. Because the numbers divisible by 3 come last in every set of 3 numbers, we can discard the remainder. Therefore there are 16 numbers between 1 and 50 that are divisible by 3.

A minute has 60 seconds. Divide by 60 (with remainder); the integer result of the division is the minutes, and the remainder is the seconds.

Divide the inches by 12 (integer division). The integer result is the number of feet. The remainder is the number of inches.

The infinitely many numbers of the form 162*k where k is any integer.

The infinitely many numbers of the form 347*k where k is any integer.