How many numbers are 10 unitβs from 0 on the number line
Oh, dude, that's an easy one. So, if we're talking about numbers that are 10 units away from 0 on the number line, we basically just need to count the numbers that are 10 units to the left and 10 units to the right of 0. That's like a total of 21 numbers, because you've got 0 in the middle and then 10 numbers on either side. Easy peasy!
there r millons and millons and millons of numbers so there is no exted number of numbers
Yes. In fact, a number line would be full of an uncountably many infinite number of discontinuities (holes) without them and hence would not be a line, so in fact irrational numbers MUST be placed on the number line in order for it to exist.
There are an infinite amount of numbers between zero (0) and one (1).
0 Look at the product of the first 3 prime numbers: 2 x 3 x 5 = 30. Any number multiplied by 30 will have a 0 in the units digit. So, no matter how many prime numbers you are multiplying, if once you have a number ending in 0, all of the rest will end in 0.
There are infinitely many numbers between them. In decimal form, any number that starts with 1. and is not followed by a string of zeros, will lie between 1 and 2.
the scale would be how many units or numbers you go by each line in the line graph.
-210
10
The number line from 1 to 10 includes 10 integers, but an infinite number of real numbers.
7
there r millons and millons and millons of numbers so there is no exted number of numbers
A number line stretches out for infinity. So, infinity.
7
Prime numbers are pure numbers, without units or dimensions.
Yes. In fact, a number line would be full of an uncountably many infinite number of discontinuities (holes) without them and hence would not be a line, so in fact irrational numbers MUST be placed on the number line in order for it to exist.
8 3
it's 5