500. Since they alternate, half the numbers between 1 and 1000 are odd and the other half are even. Adding zero to the list does not change the number of odds.
Thirteen.
They are all the 4 digit numbers starting with 1 and ending with 1, 3, 5, 7 or 9. Since there are 500 of them, I will not list them.
1 + 3 + 5 + .... + 995 + 997 + 999 = 250000
97531 + 500 = 98031.
500
[object Object]
The sum of the odd numbers (from 1) up to to 500 is 62500. The sum of an arithmetic series is given by: sum = 1/2 x number_in_series x (first + last) For the odd numbers from 1 to 500, there is: number_in_series = 250 first = 1 last = 499 which gives the sum as: sum = 1/2 x 250 x (1 + 499) = 62500.
The sum of all the odd numbers between 1 and 499 is 62500, because there are 125 pairs adding up to 500. 125 x 500 = 62500
26
500. Since they alternate, half the numbers between 1 and 1000 are odd and the other half are even. Adding zero to the list does not change the number of odds.
There are 48/2 + 1 = 25 odd numbers in 1 to 49, inclusive.
Thirteen.
The sum of all odd numbers, up to the odd number (2n-1) is n^2. So the sum of the first 1000 or 10^3 odd positive numbers is (10^3)^2=10^6 Now divide by 10^3 or 1000 since we have 1000 numbers so we have 10^6/10^3=1000 The mean of the first 1000 positive odd numbers is 1000 If you ask the mean of the odd numbers between, 1 and 1000, that is another problem, since there are 500 of them, the answer would be 500^2/500=500 Think of the mean of the odd numbers between 1 and 10, there are 5 of them and there sum is 25 so the mean is 25/5 or 5 **** in general, the arithmetic mean of the first n odd numbers is n^2/n or n. So that is why the number is 1000.
write the number that is 500 more than the biggest number that can be formed by all the odd 1 digit number
They are all the 4 digit numbers starting with 1 and ending with 1, 3, 5, 7 or 9. Since there are 500 of them, I will not list them.
501