Best Answer

n(n+1) <10000 so n is close to square-root of 10000 which is 100. Obviously 100x101 is too much, but 99x100 is OK

Q: How many pairs of consecutive integers have a product less than 10000?

Write your answer...

Submit

Still have questions?

Continue Learning about Basic Math

4 and 5 5 and 6 Any consecutive integers greater than one.

Factor pairs refer to integers, not decimals.

Integers are the "counting numbers" and their negative counterparts, and zero. Opposite integers are the pairs of integers that have the same absolute value, or, in other words, are the same distance from zero. 10 and -10 are opposite integers. 43 and -43 are opposite integers. It's just that simple.

Consecutive whole numbers are integer pairs of the form n and n+1. There can be no integer, such as 110, between such numbers.

There is only one pair of consecutive prime numbers, and the prime numbers are two and three, because any pair of consecutive numbers has one odd and one even number, and two is the only even prime number, because all other even numbers can be divided by two, and the only pairs of consecutive numbers are one and two and three, but one is not prime because it only has one factor, thus making the only consecutive pair of primes two and three. But the problem asks for the product of the two numbers, not the numbers themselves, so just multiply two and three together to get a final result of six.

Related questions

Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.

There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.

The GCF is 1. Anytime there are two consecutive integers, their GCF will be 1.

1 and 40, 2 and 20 others include: 4 and 10 5 and 8 so there aren't just two, their are four pairs of integers whose product is 40.

Although not specified as such, "consecutive" requires the numbers to be integers. Two pairs literally means four numbers but there are not four consecutive integers that add up to to 5280. 1318 + 1319 + 1320 + 1321 = 5278 and 1319 + 1320 + 1321 + 1322 = 5282. Four consecutive numbers must add up to an even number that is not a multiple of 4. If by two pairs, the question meant ONE pair (!!), again there is no answer since the sum of any pair of consecutive numbers must be an odd number.

It's any set of consecutive integers that are composite. For instance, 8, 9, and 10 are consecutive composites.

Pick any pair of prime numbers. 5, 7 11, 13 17, 19 Pick any pair of consecutive integers.

The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.

(-91,1)(-13,7)(91,-1)(13,-7)

4 and 5 5 and 6 Any consecutive integers greater than one.

16x625= 10000

1 is the only common factor of 25 and 26. 25 and 26 are "relatively prime," as are all pairs of consecutive integers.