To solve this problem, we can use Fermat's Little Theorem, which states that if p is a Prime number and a is any integer, then a^p ≡ a (mod p). Given that 29^p + 1 is a multiple of p, we can rewrite this as 29^p ≡ -1 (mod p). This implies that p must be a prime of the form 4k + 1, where k is a non-negative integer. Therefore, there are infinitely many prime numbers p that satisfy the given condition.
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
As a product of its prime factors: 2*2*2*3*3*5 = 360
The prime factorization of 80 is 2^4 * 5. This means that 80 can be expressed as the product of the prime numbers 2 and 5 raised to certain powers. In this case, 2 is raised to the power of 4 and 5 is raised to the power of 1.
The least common multiple of two different prime numbers is the product of those two prime numbers.
There is no LCM for less than two numbers. LCM is the multiple of the highest power of prime factors in two or more numbers. Example: LCM of 9, 15, and 25 is 225, which is the multiple of the highest power of prime factors in 9, 15, and 25 (32 x 52).
Any prime number raised to a power.
There are infinitely many prime numbers and there is no greatest prime. So there cannot be an answer to the question.
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
2^6 x 3 = 192
As a product of its prime factors: 2*2*2*3*3*5 = 360
The prime factorization of 80 is 2^4 * 5. This means that 80 can be expressed as the product of the prime numbers 2 and 5 raised to certain powers. In this case, 2 is raised to the power of 4 and 5 is raised to the power of 1.
The least common multiple of two different prime numbers is the product of those two prime numbers.
No there isn't. every perfect square number can be factored into prime number. At their factoration you'll always have multiples of two on the primes exponent. Therefore you'll multiply a prime raised to a 2-multiple number with another prime raised to a 2-multiple number wich gives you also a number that factored gives you a product of prime numbers raised to a 2-multiple number and so, a perfect square.
42
There is no LCM for less than two numbers. LCM is the multiple of the highest power of prime factors in two or more numbers. Example: LCM of 9, 15, and 25 is 225, which is the multiple of the highest power of prime factors in 9, 15, and 25 (32 x 52).
2 and 3 are prime numbers 48 is a multiple of.
There is no LCM for less than two numbers. LCM is the multiple of the highest power of prime factors in two or more numbers. Example: LCM 0f 9, 15, and 25 is 225, which is the multiple of the highest power of prime factors in 9, 15, and 25 (32 x 52).