All prime numbers greater than 2 are odd numbers. For an odd prime to be written as the sum of two primes, one of the primes must be 2 because two odd primes will produce an even sum. 11 cannot be written as the sum of two primes. 13 = 2 + 11. 17 cannot be written as the sum of two primes. 19 = 2 + 17.
2 + 3 = 5
23+29+31+37+41+47+53+59 = 320
The primes between ten and twenty are 11, 13, 17 and 19. Adding them together gives 60.
All of these could yield an integer when divided by 10. 1. sum of two integers: ( 10 + 10)/10 = 2 2. integer less than 10: -20 < 10 and -20/10 = -2 3. product of 2 primes: 2 and 5 are primes and 2*5/10 = 1 4. sum of three consecutive integers ; (9+10 + 11) /10 3
All prime numbers greater than 2 are odd numbers. For an odd prime to be written as the sum of two primes, one of the primes must be 2 because two odd primes will produce an even sum. 11 cannot be written as the sum of two primes. 13 = 2 + 11. 17 cannot be written as the sum of two primes. 19 = 2 + 17.
2 + 3 = 5
23+29+31+37+41+47+53+59 = 320
5, 7, 13, 17 and 19 can be so written.
There are 9 prime numbers between 0 and 20: 1,2,3,5,7,11,13,17,19.
20 as a product of primes = 2 * 2 * 5
Three sets
80.46 sets
The primes between ten and twenty are 11, 13, 17 and 19. Adding them together gives 60.
All of these could yield an integer when divided by 10. 1. sum of two integers: ( 10 + 10)/10 = 2 2. integer less than 10: -20 < 10 and -20/10 = -2 3. product of 2 primes: 2 and 5 are primes and 2*5/10 = 1 4. sum of three consecutive integers ; (9+10 + 11) /10 3
Oh, dude, it's like simple math time! If you want to know how many sets of 20 are in 800, you just divide 800 by 20. So, 800 divided by 20 equals 40 sets of 20. Easy peasy lemon squeezy!
To find out how many sets of 20 are in 700, you would divide 700 by 20. This division would result in 35 sets of 20 in 700. Each set of 20 would be a whole number without any remainder.