One set is: 2+7+11 = 20
2? Not sure
All prime numbers greater than 2 are odd numbers. For an odd prime to be written as the sum of two primes, one of the primes must be 2 because two odd primes will produce an even sum. 11 cannot be written as the sum of two primes. 13 = 2 + 11. 17 cannot be written as the sum of two primes. 19 = 2 + 17.
2 + 3 = 5
23+29+31+37+41+47+53+59 = 320
List the primes up to 20 (2, 3, 5, 7, 11, 13, 17, 19) and note that the largest possible prime in the sum is 13 because no two primes add up to and of course 19 is too large as well. Also, observe that 2, the only even prime, must be in the sum, because the sum of three odd primes cannot never be 20. Starting with 2 and 3, we see that is not prime. Next, 2 and 5 give , a prime, so one such increasing sequence is 2, 5, 13. Next, we take 2 and 7, and we see that is prime as well, giving us the second sequence 2, 7, 11. 11 and 13 are already included, so we are done. Thus, there are increasing sequences of three distinct prime numbers that have a sum of 20.
The primes between ten and twenty are 11, 13, 17 and 19. Adding them together gives 60.
All prime numbers greater than 2 are odd numbers. For an odd prime to be written as the sum of two primes, one of the primes must be 2 because two odd primes will produce an even sum. 11 cannot be written as the sum of two primes. 13 = 2 + 11. 17 cannot be written as the sum of two primes. 19 = 2 + 17.
2 + 3 = 5
23+29+31+37+41+47+53+59 = 320
5, 7, 13, 17 and 19 can be so written.
There are 9 prime numbers between 0 and 20: 1,2,3,5,7,11,13,17,19.
List the primes up to 20 (2, 3, 5, 7, 11, 13, 17, 19) and note that the largest possible prime in the sum is 13 because no two primes add up to and of course 19 is too large as well. Also, observe that 2, the only even prime, must be in the sum, because the sum of three odd primes cannot never be 20. Starting with 2 and 3, we see that is not prime. Next, 2 and 5 give , a prime, so one such increasing sequence is 2, 5, 13. Next, we take 2 and 7, and we see that is prime as well, giving us the second sequence 2, 7, 11. 11 and 13 are already included, so we are done. Thus, there are increasing sequences of three distinct prime numbers that have a sum of 20.
20 as a product of primes = 2 * 2 * 5
Three sets
80.46 sets
The primes between ten and twenty are 11, 13, 17 and 19. Adding them together gives 60.
4
All of these could yield an integer when divided by 10. 1. sum of two integers: ( 10 + 10)/10 = 2 2. integer less than 10: -20 < 10 and -20/10 = -2 3. product of 2 primes: 2 and 5 are primes and 2*5/10 = 1 4. sum of three consecutive integers ; (9+10 + 11) /10 3