5 with a remainder of 15
These problems are trivial to do in your head.
The common factors of 25 and 140 are: 1, 5
the common factors of 140 and 25 are 1, and 5
1, 5, 25 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140
15% of 200 = 3025% of 140 = 35
It is: 25%
5 goes into 140 28 times.
To calculate how many times 25 goes into 220, you would perform the division operation 220 รท 25. The result of this division is 8, with no remainder. Therefore, 25 goes into 220 exactly 8 times.
'25' goes in to 140 , 5 times , with a remainder of '15'. 140/25 Cancel down by '5' 28/5 Fives goes in to 28, 5 times with a remainder of '3'. Multiply '3' by '5' ; 3 X 56 = 15 and you are back to the original remainder.
Once - with a remainder of 15.
5 with 15 remaining 140 - 15 = 125 = 25 x 5
4*25+40=140
To determine how many times 25 goes into 84, you would perform long division. When you divide 84 by 25, the quotient is 3 with a remainder of 9. Therefore, 25 goes into 84 three times with a remainder of 9.
To determine how many times 25 goes into 234, you would perform a division operation. 234 divided by 25 equals 9 with a remainder of 9. This means that 25 goes into 234 a total of 9 times, with a remainder of 9.
GCF of 140 and 25 is 5.
The answer is 3.4
To find out how many times 25 goes into 88, you would perform long division. When you divide 88 by 25, you get a quotient of 3 with a remainder of 13. Therefore, 25 goes into 88 three times with a remainder of 13.
To determine how many times 25 goes into 60, you would perform the division operation 60 รท 25. The result is 2, with a remainder of 10. Therefore, 25 goes into 60 two times, with a remainder of 10.