The answer depends on what the tens digit is greater than, and what the ones digit does then.
It is 9 times greater.
16
Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.
Probably 73.
Composite numbers can have any digit in the ones place: All multiples of 3 greater than 10 will be composite numbers (the first one being 3×4 = 12). The last digit of the multiples of 3 follow the pattern (starting at 12, ending at 39): {2, 5, 8, 1, 4, 7, 0, 3, 6, 9} which includes all the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. Thus the last digit of composite numbers greater than 10 can contain any digit.
There are 45 of them.
-3
4
It is 9 times greater.
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45 (10,20,21 etc etc)
91
How about: 11, 13, 17, 19 .... etc
Is it only 890 and 891
Composite numbers are integers greater than 1 that can be divided evenly by numbers other than 1 and themselves. In the case of numbers up to 100, the unit's digit refers to the digit in the ones place. The claim that composite numbers up to 100 have 1 as their unit's digit is incorrect, as composite numbers can have any digit in the ones place depending on their factors.
Since cents are only in whole numbers, you look at the digit directly to the right of the ones digit. In this case, it is a 7. Since that is 5 or greater, the ones digit is rounded up. The answer is 16 cents.
23
8 of them.