DeltaG = DeltaH - TDeltaS
dG = -54.32 kJ/mol - (54'32+273)K(-354.2J/molK)
NB Thevtemperature is quoted in Kelvin(K) and the Entropy must be converted to kJ by dividing by '1000'/
Hence
dG = - 54.32kJ/mol - (327.32K)(-0.3542 kJ/molK)
NB The 'K' cancels out. Then maker the multiplication
dG = -54/32 kJ/mol - - 115.94 kJ/mol Note the double minus; it becomes plus(+).
Hence
dG = -54.32kj/mol + 115.94 kJ/mol
dG = (+)61.61 kJ/mol
Since dG is positive, the reaction is NOT thermodynamically feasible.
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The answer depends on what two (or more) things the ratio is meant to compare. The kinetic energy of several objects? The kinetic energy of an object compared to its total energy? The kinetic energy compared to its engine size?
Potential energy does not depend on an object's decimal compulsion composition.
Basal Metabolism (BMR)
Joule is a unit for measuring energy. Meter is a unit for measuring length or distance. There is no conversion. If you wanted to find the potential energy of an object, 2.04 meters off the ground, then you would need to know the mass of the object and the value of g (gravitational acceleration) at the point where you are, then you could calculate energy in Joules.
Look for the ct (current transformer). You will find a ratio rating (for example, 200:5.) This means divide 200 by 5. The result is 40. Any difference in reading from a certain time should be multiplied by 40 to get actual energy consumption. This is the basic information, but in practice it should be calibrated by a government-certified body (the department of energy, for example) to perfectly match the kwhr-meter revolution.