28 percent of 80 percent is 22.4 percent.
28 percent of 9,600.00 is 2,688.
28%= 28/100 = 7/25
28 percent of 120.50 = .28 x 120.50 = 33.74
28/0.7 = 40 Therefore, 28 is 70 percent of 40.
You divide by two. The percentage is 14%
Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.
There is nothing average about beer, and beer is not typically proofed like distilled alcohol is, but let's work this out.The average AbV (Alcohol by Volume) of domestic beer in the US is 3.5%. That would be a proof of 7.The average AbV of microbrews in the US is about 7.5, making that proof 15.The highest domestic AbV of a US brewed beer is Sam Adams' Utopias at 28%, putting the proof at 56.The highest AbV of any beer in the world is Brewmeister Armageddon from Scotland at 68%, or 130 proof.
35 percent of fatal crashes involve alcohol use.
28 percent of 80 percent is 22.4 percent.
(Note: This answer assumes that the "ounces" specified are avoirdupois or other weight ounces and that percentages are by weight; otherwise possible volume changes on dilution must by considered.) The weight of pure alcohol in each solution is the product of the percentage and the total weight of the solution. Therefore, designating the unknown weight of 30 % alcohol as w, from the problem statement 0.30w + 0.80(40) = 0.70(w + 40), or 0.30w + 32 = 0.70w + 28, or 32 - 28 = w(0.70 - 0.30) or w = 4/0.40 = 10 ounces of 30 % alcohol.
28 percent is 0.28
28 percent of 9,600.00 is 2,688.
28 percent of 130 is 36.4
0.9128 is 28 percent of 3.26.
Percent of 13 out of 28 is 46.43.
28 percent of 18,000 is 5,040.