Let R + S = T, and suppose that T is a rational number.The set of rational number is a group.This implies that since R is rational, -R is rational [invertibility].Then, since T and -R are rational, T - R must be rational [closure].But T - R = S which implies that S is rational.That contradicts the fact that y is an irrational number. The contradiction implies that the assumption [that T is rational] is incorrect.Thus, the sum of a rational number R and an irrational number S cannot be rational.
If the 6's continue, it is -5/3, and therefore it is rational. If they do not continue, it is -166/100, and still rational.
yes
681
Yes.
Yes
Let R + S = T, and suppose that T is a rational number.The set of rational number is a group.This implies that since R is rational, -R is rational [invertibility].Then, since T and -R are rational, T - R must be rational [closure].But T - R = S which implies that S is rational.That contradicts the fact that y is an irrational number. The contradiction implies that the assumption [that T is rational] is incorrect.Thus, the sum of a rational number R and an irrational number S cannot be rational.
The product of two rational numbers is always a rational number.
No.
Whether that's all there is to it, or the '135's keep going on forever, either way, it's a rational number.
Whether that's all there is to it, or the '135's keep going on forever, either way, it's a rational number.
If the 6's continue, it is -5/3, and therefore it is rational. If they do not continue, it is -166/100, and still rational.
It is a rational number. It can be written as a fraction.
no # all numbers are real #'s
Rational. It can be expressed a s fraction having integers for the denominator and numerator. ie 93,808,315/100,000,000
yes
Given a rational number, express it in the form of a ratio. You can then calculate equivalent rational fractions if you multiply both, its numerator and denominator, by any non-zero integer.