no - 0.333333 is 333333/1000000, which is the ratio of two integers, the denominator not being zero, and that meets the definition of a rational number. Also, 0.333333, with the 3's repeating forever is 1/3, also a rational number.
yes
Yes.
It must be a generalised rational number. Otherwise, if you select a rational number to multiply, then you will only prove it for that number.
yes
A terminating or repeating decimal is rational. .333333...=1/3 5.09090909=509090909/100000000
no - 0.333333 is 333333/1000000, which is the ratio of two integers, the denominator not being zero, and that meets the definition of a rational number. Also, 0.333333, with the 3's repeating forever is 1/3, also a rational number.
There are infinitely many pairs of number. Let A be any number and let B = A + 333333.Then B - A = A + 333333 - A = 333333.Since The choice of A is arbitrary so A could be any one of infinitely many numbers. Therefore, there are infinitely many solutions.
It is a rational number. It can be written as a fraction.
yes
.333333 is not an integer. An integer is a whole number like 1, 2, 3...
Is 12.05 a rational number or irrational number?
1.96 is a rational number
It is a rational number, as it can be written as a fraction.
Yes, the sum is always rational.
33.3333 is a fraction. It is a fraction in decimal form rather than in the form of a ratio. However, that does not stop it being a fraction. Its rational equivalent is 333333/10000 which cannot be simplified.
There is no such thing as a number that is both rational and irrational. By definition, every number is either rational or irrational.