Electrons are removed first from the 5d orbital than the 4f orbital in lanthanides because the 5d orbital has higher energy than the 4f orbital. In lanthanides, the energy difference between the 4f and 5d orbitals is small, making it more energetically favorable to remove electrons from the 5d orbital first before the 4f orbital.
The 4s orbital has the greatest shielding effect because it is the closest to the nucleus and experiences less shielding from inner electrons compared to the 4p, 4d, and 4f orbitals. This means that electrons in the 4s orbital are held less tightly by the nucleus and are more easily removed.
3 nodes in 4f
The possible values for a 4f sublevel are 14. This means there can be a maximum of 14 electrons in a 4f sublevel.
This question is tricky because distance and location are not well defined within the electron cloud. So for the sake of explanation, let us assume that the question is "Which has a region maximum probability closest to the nucleus?" I could not find an answer in print for the 4f vs 6s. However, I did find an answer comparing the 3d and 4s. I believe that an understanding of a comparison between the 3d and 4s can be extended to a comparison between the 4f and 6s. The most probable distance of the 3d is less than the 4s. Therefore, we could extend this and say that most likely the 4f sublevel would have a distance of maximum probability closer than the 6s. You did not ask why so I will not go into an explanation.
Electrons are added to the 4f orbitals from the 5d orbitals in the lanthanide and actinide series of elements. The 4f orbitals are filled after the 5d orbitals are filled due to the overlap in energy levels, leading to the stability of the 4f electrons in these elements.
There are seven 4f orbitals in an atom: 4f sublevel consists of seven orbitals, each designated as 4f_x, where x ranges from -3 to +3.
The elements of the 4f series are called lanthanides. They are a group of metallic elements that have similar properties and occupy the f-block of the periodic table.
The 5s orbital has a lower energy level than the 4d or 4f orbitals in a rubidium atom, according to the aufbau principle. Electrons fill orbitals starting from the lowest energy level to the highest energy level. This is why the electron fills the 5s orbital before the 4d or 4f orbitals in a rubidium atom.
Yes, "4f" is a valid orbital shell designation in the electronic configuration of atoms. It represents the fourth energy level and the f subshell within that energy level.
The energy sublevel being filled by the elements Ce to Lu is the 4f sublevel. These elements are part of the lanthanide series and have their outermost electrons entering the 4f orbital.
When you have 3f plus f plus 4f, you are adding together like terms. In this case, the variable "f" is the same, so you can add the coefficients together. 3f + f is 4f, and when you add 4f to that, you get 8f. Therefore, 3f + f + 4f equals 8f.