If you want to know if a number is prime or composite, begin by looking at it. The last digit of 432 is even; that means that 432 is divisible by two, so it can't be prime. Look again. Add up the digits of 432. 4 + 3 + 2 = 9. 9 is divisible by 3, so 432 is divisible by 3. Not prime. In fact 432 is about as composite as you can get. It is 2 X 2 X 2 X 2 X 3 X 3 X 3.
The prime factorization of 432 is 2 * 2 * 2 * 2 * 3 * 3 * 3 or 2^4 * 3^3
It is divisible by 2, 3, 4, 6 and 9.
To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.
To find the Greatest Common Factor (GCF) of 88, 48, and 432, we first need to find the prime factorization of each number. 88 = 2^3 * 11 48 = 2^4 * 3 432 = 2^4 * 3^3 Next, we look for the common prime factors among the numbers, which are 2^3 = 8. Therefore, the GCF of 88, 48, and 432 is 8.
432/3 = 144 432/4 = 108 432 is divisible by both 3 and 4.
432 is divisible by 3 and 4 because the quotients are whole numbers. 432/3 = 144 432/4 = 108
None of them. 432 is divisible by 2, 3, 4, 6, 8 and 9.
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
The digital root of 432 is 9 so the number is divisible by 3. The number formed by the last two digits, 32, is divisible by 4 (4*8) so 432 is divisible by 4.
No.
If you want to know if a number is prime or composite, begin by looking at it. The last digit of 432 is even; that means that 432 is divisible by two, so it can't be prime. Look again. Add up the digits of 432. 4 + 3 + 2 = 9. 9 is divisible by 3, so 432 is divisible by 3. Not prime. In fact 432 is about as composite as you can get. It is 2 X 2 X 2 X 2 X 3 X 3 X 3.
432 can be expressed as the product of its prime factors, which are 2, 2, 2, 2, 3, 3, 3. This can be written as 2^4 * 3^3. Additionally, 432 is the sum of the first 20 even numbers starting from 2. In mathematics, 432 is considered a Harshad number, as it is divisible by the sum of its digits (4 + 3 + 2 = 9, and 432 รท 9 = 48).
Yes, by 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 27, 36, 48, 54, 72, 108, 144, 216, 432
The prime factorization of 432 is 2 * 2 * 2 * 2 * 3 * 3 * 3 or 2^4 * 3^3
1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 27, 36, 48, 54, 72, 108, 144, 216, 432
432, 468