Best Answer

yes

432/2 = 216

432/3 = 144

432/4 = 108

432/6 = 72

432/8 = 54

432/9 = 48

More answers

Lvl 1

yes

Q: Is 432 divisible by 2 3 4 6 8 9?

Write your answer...

Submit

Still have questions?

Continue Learning about Basic Math

If you want to know if a number is prime or composite, begin by looking at it. The last digit of 432 is even; that means that 432 is divisible by two, so it can't be prime. Look again. Add up the digits of 432. 4 + 3 + 2 = 9. 9 is divisible by 3, so 432 is divisible by 3. Not prime. In fact 432 is about as composite as you can get. It is 2 X 2 X 2 X 2 X 3 X 3 X 3.

The prime factorization of 432 is 2 * 2 * 2 * 2 * 3 * 3 * 3 or 2^4 * 3^3

It is divisible by 2, 3, 4, 6 and 9.

The prime factors of 432 are 2 and 3 (2^4 x 3^3).The prime factorization is 2 x 2 x 2 x 2 x 3 x 3 x 3 (equal to 16 x 27).

Its digits add up to a multiple of 3.

Related questions

432/3 = 144 432/4 = 108 432 is divisible by both 3 and 4.

432 is divisible by 3 and 4 because the quotients are whole numbers. 432/3 = 144 432/4 = 108

None of them. 432 is divisible by 2, 3, 4, 6, 8 and 9.

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.

The digital root of 432 is 9 so the number is divisible by 3. The number formed by the last two digits, 32, is divisible by 4 (4*8) so 432 is divisible by 4.

No.

If you want to know if a number is prime or composite, begin by looking at it. The last digit of 432 is even; that means that 432 is divisible by two, so it can't be prime. Look again. Add up the digits of 432. 4 + 3 + 2 = 9. 9 is divisible by 3, so 432 is divisible by 3. Not prime. In fact 432 is about as composite as you can get. It is 2 X 2 X 2 X 2 X 3 X 3 X 3.

Yes, by 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 27, 36, 48, 54, 72, 108, 144, 216, 432

The prime factorization of 432 is 2 * 2 * 2 * 2 * 3 * 3 * 3 or 2^4 * 3^3

1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 27, 36, 48, 54, 72, 108, 144, 216, 432

432, 468

1 2 3 4 6 8 9 12 16 18 24 27 36 48 54 72 108 144 216 432.