Any multiple of 56.
Missing factors -?,2,?,7,8,14,28,56
The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.
Their lowest common multiple is 56
The LCM of 4, 8, and 14 is 56
56
Since 56 is a multiple of 8, it is automatically the LCM.
The least common multiple of the numbers 7 and 8 is 56.
The least common multiple of the numbers 8, 14 and 7 is 56.
The LCM is 56.
The Least Common Multiple (LCM) for 8 7 is 56.
The LCM is 56.
56
56
The smallest multiple of 8 and 14 is 56.
56
56