Oh, dude, you're hitting me with the math questions. Okay, so a rational number is any number that can be expressed as a fraction, right? And 6.28 can totally be written as 628/100, which is a fraction, so yeah, it's a rational number. But like, who even uses fractions these days anyway?
In mathematics, the concept of a "ring" refers to a specific algebraic structure. The number 628 being on a ring does not inherently imply that it is a real number. In the context of rings, elements can be integers, rational numbers, complex numbers, or other mathematical objects, but the term "real" typically refers to a subset of numbers on the real number line. Therefore, without additional context or clarification, it is not accurate to conclude that 628 being on a ring means it is a real number.
yes
Yes.
It must be a generalised rational number. Otherwise, if you select a rational number to multiply, then you will only prove it for that number.
yes
It is not. It is the rational number 6.28 = 628/100.
In mathematics, the concept of a "ring" refers to a specific algebraic structure. The number 628 being on a ring does not inherently imply that it is a real number. In the context of rings, elements can be integers, rational numbers, complex numbers, or other mathematical objects, but the term "real" typically refers to a subset of numbers on the real number line. Therefore, without additional context or clarification, it is not accurate to conclude that 628 being on a ring means it is a real number.
It is a rational number. It can be written as a fraction.
yes
Is 12.05 a rational number or irrational number?
1.96 is a rational number
(650) 628-4322
It is a rational number, as it can be written as a fraction.
Yes, the sum is always rational.
There is no such thing as a number that is both rational and irrational. By definition, every number is either rational or irrational.
As much as, in these days of uncertainty, anything can be anything. As long as the constraints of a rational number are kept to, a rational number will always remain a rational number.
Yes, it is.