Yes, 6 is a factor of 492. If you divide 492 by 6 you get 82 with no remainder. The fact that there was no remainder means that the first number is a factor of the second number.
Taking this to the obvious conclusion; the prime factors of 492 are 2, 2, 3, and 41. 6 is 2 times 3, so it is a non prime factor, but it is a factor nontheless.
6 is a factor of 492.
Yes it is. 2 is a factor because 492 ends in 2, 3 is a factor because 4+9+2 is divisible by 3. So 6 is a factor.
no it its not im only 11 and i know it
No, 18 is a multiple of 6. 6 is a factor of 18.
no 6 is not a factor of 56
6 is a factor of 492.
Yes. If 492 is even, it has 2 as a factor. If its digits add up to a multiple of 3, it has 3 as a factor. If it has 2 and 3 as a factor, it has 6 as a factor.
It is a factor because 6 goes into 492 evenly
492 is an even number so it must be divisible by 2. Its digits total a multiple of 3 so it must be divisible by 3. Any even number that is divisible by 3 is divisible by 6. Of course, you can always divide 492 by 6. If it comes out even, it's a factor. (It does.)
Yes it is. 2 is a factor because 492 ends in 2, 3 is a factor because 4+9+2 is divisible by 3. So 6 is a factor.
6 x 82 = 492
492 ÷ 6 = 82
No, because 6 is not a factor of 50.
6 is a factor of 246 because 6 divides evenly into 246 with no remainder.
82.6667
492
492