Yes.
Here's how to prove it.
Try dividing 713 by all the primes below its square root.
Take the square root, rounded down: 26
Find the largest prime below that: 23
Try dividing 713 by 23, 19, 17, 13, 11, 7, 5, 3, 2 (all the primes from 23 down).
It doesn't divide evenly into any of them so it must be prime.
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713 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 4 factors of 713 are 1, 23, 31, and 713.The factor pairs of 713 are 1 x 713 and 23 x 31.The proper factors of 713 are 1, 23, and 31 or,if the definition you are using excludes 1, they are 23 and 31.The prime factors of 713 are 23 and 31The 2 distinct prime factors (listing each prime factor only once) of 713 are 23 and 31.The prime factorization of 713 is 23 x 31.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
You is called a prime number!You is called a prime number!You is called a prime number!You is called a prime number!
A prime number times a prime number is a composite number. Since prime numbers, except for 2, are odd numbers, a prime number times a prime number is usually an odd number. It will only be an even number if one of the prime numbers is 2. A prime number times a prime number will be a number with four factors unless both prime numbers are the same, in which case it will be a square number with only three factors.
101 is a prime number. The only factor of 101 is itself and 1.prime
37 is an odd prime number