No, it is not. 77 is divisible by 7 & 11, not just itself & 1. A prime number is a natural number which has exactly two distinct natural number divisors: 1 & itself.
77 is not a Prime number because it has more than two factors
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NO!!!!
It is a compound number, because it is the product of 7 & 11
7 x 11 = 11 x 7 = 77
As 77 = 7 x 11, any number that is not a multiple of 7 or 11 is relatively prime to 77, e.g. 25, 38, 123
77 = 7 x 111,7, and 11 are the prime factors of 771x7x11=77
7 is a factor of 77 so it cannot be a prime. So it has to be composite.It is composite since 7 x 11 is 77 and those are both primes. That is to say, it is the product of two primes and that makes it composite.
77 is a composite number; it has factors other than 1 and itself. It is not a prime number.The four factors of 77 are 1, 7, 11, and 77.The factor pairs of 77 are 1 x 77 and 7 x 11.The proper factors of 77 are 1, 7, and 11 or,if the definition you are using excludes 1, they are 7 and 11.The prime factors of 77 are 7 and 11.The 2 distinct prime factors of 77 are also 7 and 11, since there is no repetition of factors.The prime factorization of 77 is 7 x 11.
The prime factorization of 77 is 7 x 117 x 11 = 77