Yes, it's always odd, and here's the proof:
All odd numbers can be expressed as 2p + 1, where p is any integer.
Multiply two of those together:
(2n + 1)(2p + 1) = 4np + 2n + 2p + 1 = 2(np + n + p) + 1.
Since both np, n, and p are integers, that means np + n + p is an integer; and since that integer is being multiplied by 2, it must be even. Thus, by adding 1 to that even number, the result will be odd.
In the same way that and odd plus and even is always odd. For example, 7*3 = (7+7) odd + odd = even , then add +7, apply rule that odd + even = odd and get that it equals 21.
even times even = even odd times even = even odd times odd = odd
The GCF of any two odd numbers is always odd. The GCF of any two even numbers is always even. The GCF of an odd and an even number is always odd.
The sum of three whole odd numbers will always be odd keeping in mind that zero is neither even nor odd and that 'null' is not a number.
opposite - answer will always be odd (when adding odd + even) odd + even 5 + 4 = 9 odd even + even 2 + 6 = 8 even odd + odd 3 + 1 = 4 even
Yes, it is.
Yes. Odd times odd is odd. Odd times even is even. Even times even is even.
No. In fact, you NEVER get an odd number.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times odd is always odd.
In the same way that and odd plus and even is always odd. For example, 7*3 = (7+7) odd + odd = even , then add +7, apply rule that odd + even = odd and get that it equals 21.
yes
No. 2 x 3 = 6
The sum of two odd numbers is always even; the sum of three odd numbers is always odd; the sum of four odd numbers is always even; the sum of five odd numbers is always odd; etc
Yes. One has to be the square of an odd number. The other square has to the the square of the even number either before or after the odd number. If this is confusing just plug in real values. In either case, an odd times and odd is odd. Therefore one of the squares has to be odd. AN even times an even, however, is always even. Therefore, the second square has to be even. Thus, one of the squares is even and the other is odd. An even plus and odd is always odd.
even times even = even odd times even = even odd times odd = odd
Let me show this to you by an example : Suppose we wish to multiply 3 and 7. Product or Multiplication by any device is actually carried by the process of addition of 3 seven times, i.e. 3+3+3+3+3+3+3 = 21. Because the two numbers are odd, the result is always odd. To Summarize, addition of an odd number(i.e. 3) to itself an odd number of times(i.e. 7) always results in an odd number. The product of an even and an odd number always results in an even number because addition of even number any number of times is always even and an odd number added to itself an even number of times also results in an even number. For ex. 7*2 = 14, here 7(odd number) is added 2(even number) times, i.e. 7+7=14 which is even.
The result will always be an odd number.