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Yes, it's always odd, and here's the proof:
All odd numbers can be expressed as 2p + 1, where p is any integer.
Multiply two of those together:
(2n + 1)(2p + 1) = 4np + 2n + 2p + 1 = 2(np + n + p) + 1.
Since both np, n, and p are integers, that means np + n + p is an integer; and since that integer is being multiplied by 2, it must be even. Thus, by adding 1 to that even number, the result will be odd.
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Why is odd times odd numbers always odd numbers?
In the same way that and odd plus and even is always odd. For example, 7*3 = (7+7) odd + odd = even , then add +7, apply rule that odd + even = odd and get that it equals 21.
Is even times even odd?
even times even = even odd times even = even odd times odd = odd
Is the GCF of any two even numbers is always even?
The GCF of any two odd numbers is always odd. The GCF of any two even numbers is always even. The GCF of an odd and an even number is always odd.
The sum of three odd numbers is always odd true or false?
The sum of three whole odd numbers will always be odd keeping in mind that zero is neither even nor odd and that 'null' is not a number.
If you add an odd and even number will the answer always be even?
opposite - answer will always be odd (when adding odd + even) odd + even 5 + 4 = 9 odd even + even 2 + 6 = 8 even odd + odd 3 + 1 = 4 even
